grafx1 Posted June 6, 2005 Posted June 6, 2005 Hi,Please, I would like to know what is the width and length (in cm) of a 15.4 wide screen of a Notebook ?Thank you so much .
ripken204 Posted June 6, 2005 Posted June 6, 2005 h=22.7''w=30.3''this is about what it is, give or take .1what exactly do u need this info for?
grafx1 Posted June 6, 2005 Author Posted June 6, 2005 (edited) h=22.7''w=30.3''this is about what it is, give or take .1what exactly do u need this info for?<{POST_SNAPBACK}>(i think this dimensions are for 15" not wide screen !!)i was thinking of buying a one !!!is the 15.4" wide screen comfortable or the 15"and is the text readable ?Thank you so much for your time Edited June 6, 2005 by grafx1
Zxian Posted June 6, 2005 Posted June 6, 2005 I've got a 15.4" WXGA (1280x800) display on my laptop and it's fantastic. Text is very readable. If you go for higher resolutions, it becomes more difficult to read, IMO. The widescreen also allows you to have two documents open side by side for comparison or reference. Very handy if you're learning something new and need your reference document open while you're writing your real one.Oh... and the obvious advantage of widescreen movies is there as well.
ripken204 Posted June 6, 2005 Posted June 6, 2005 crap sry, didnt know u wanted wide, but mine is a 15.4 regular screen, 1280x800
puntoMX Posted June 7, 2005 Posted June 7, 2005 Just think about it like this, the width is like a 17", hight like a 15" (a bit bigger, just 32 pix ). I sold this kind of laptops a lot last month. Cool thing; these labtops come with fast ATI cards too (brand: HP).
grafx1 Posted June 7, 2005 Author Posted June 7, 2005 (edited) Thank you all but no one told me the (height * width) of the WXGA LCD screen Thank you. Edited June 7, 2005 by grafx1
grafx1 Posted June 7, 2005 Author Posted June 7, 2005 i want to know the difference between it and my 17" CRT (16" viewable)because i'd got used to its size, and i'm afraid that 15.4" WXGA would besmall...Thanks.
Zxian Posted June 7, 2005 Posted June 7, 2005 I think there's some confusion here.ripken204, if your resolution is 1280x800 then you have a proper 16:10 aspect ratio widescreen display.For the actual dimensions, you can figure them out with some simple math. If you want, I can probably post up my work, but the end result is that the screen would beW: 36.4cm = 14.3 inH: 22.7cm = 8.95 inAs for the resolution, it depends on what you buy. WXGA is specified to be 1280x800, which I find the most comfortable for reading. Anything higher than that and you start having to strain to read text.I've got a 17" CRT monitor as well set to 1280x960 and I have no troubles going from one screen to the other.
grafx1 Posted June 7, 2005 Author Posted June 7, 2005 (edited) Thank you sooo much.can you show me how can this be calculated as you said ? Edited June 7, 2005 by grafx1
Zxian Posted June 7, 2005 Posted June 7, 2005 Since we know the ratios of the sides, we can use Pythagoras' Theorem to solve this problem (Google for more info).From here...(16x)^2 + (10x)^2 = (15.4)^2196x^2 + 100x^2 = 237.16296x^2 = 237.16x^2 = 0.80122x = 0.8951With that, we simply put these back into the corresponding side lengths from our diagram:16x = 14.310x = 8.95Since the original measurement of the diagonal was in inches, these numbers are also in inches. Multiply them by 2.54 to get them into cm.Hope this helps!
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