batch select setup from NEWEST directory

[Lolita]

Hello,

i have directory structure like this

6.1.99

6.1.100

6.1.101

6.1.102

and so on

i want to execute command setup.exe /QN1 on the newest directory (or directory with newest version number). Do you know how to do it?

[radix]

Hello,

i have directory structure like this

6.1.99

6.1.100

6.1.101

6.1.102

and so on

i want to execute command setup.exe /QN1 on the newest directory (or directory with newest version number). Do you know how to do it?

In your directory tree you have one single file wich is named setup.exe?

[Yzöwl]

Who's created the directory structure? Can you correct their names so the they are numbered correctly? Were the directories created on different dates according to your needs? Do the setup files have dates which can be used instead? etc.

[jaclaz]

In other words, this is the output of

DIR | FIND "<DIR>"

with a "right" numbering:

W:\test>dir | FIND "<DIR>"

14/02/2008 18.47 <DIR> .

14/02/2008 18.47 <DIR> ..

14/02/2008 18.45 <DIR> 6.1.099

14/02/2008 18.45 <DIR> 6.1.100

14/02/2008 18.46 <DIR> 6.1.101

and this is the output of the same command with "your" numbering:

W:\test>dir | FIND "<DIR>"

14/02/2008 18.50 <DIR> .

14/02/2008 18.50 <DIR> ..

14/02/2008 18.45 <DIR> 6.1.100

14/02/2008 18.46 <DIR> 6.1.101

14/02/2008 18.45 <DIR> 6.1.99

jaclaz

Edited February 14, 2008 by jaclaz

[Yzöwl]

However without renaming the directory:

dir/ad/od/b

will return

W:\test>dir/ad/od/b

6.1.99

6.1.100

6.1.101

6.1.102

by sorting according to date/time (oldest first).

You could then parse the output to use the latest directory.

[Lolita]

Thank you! It is a good start i think that i can handle it now with use of commandiux.