Jump to content

how to remove alcohol folder using command line


Recommended Posts

i cant remove the "Alcohol 120%" folder from start menu

i use a CMD file containing the following to perform that..

RD /s /q "C:\Documents and Settings\All Users\Start Menu\Programs\Alcohol 120%"

it didnt work..while other folders did..

i think it is the character "%" that cause the problem..can someone help to solve it?

thanks

Link to comment
Share on other sites


i cant remove the "Alcohol 120%" folder from start menu

i use a CMD file containing the following to perform that..

RD /s /q "C:\Documents and Settings\All Users\Start Menu\Programs\Alcohol 120%"

it didnt work..while other folders did..

i think it is the character "%" that cause the problem..can someone help to solve it?

thanks

This doesn't work. Why? Because there are spaces in your path. Try using %allusersprofile%, this should make it work!

Link to comment
Share on other sites

Not the problem with the spaces,i think..for i have managed to remove other folders using the same command line

e.x:

RD /s /q "C:\Documents and Settings\All Users\Start Menu\Programs\Nero"

it works fine..

Link to comment
Share on other sites

Not the problem with the spaces,i think..for i have managed to remove other folders using the same command line

e.x:

RD /s /q "C:\Documents and Settings\All Users\Start Menu\Programs\Nero"

it works fine..

Maybe...

But I'm experiencing the same problem: in Windows those commands work fine, but when installing it and the batch file runs it doesn't work at all!

Link to comment
Share on other sites

anything with more characters is cut to the first 6 and a ~1 is added to it. It's also determined by the order in which the directories were created. So if .... Alcohol2 was created before Alcohol1, Alcohol2 would be be names Alcoho~1. Either if the names were different, samething applies if the first 6 letters are the same.

Link to comment
Share on other sites

Try This

RD /s /q "%allusersprofile%\Start Menu\Programs\Alcohol 120%"

and the dos folder name is the first six characters of folder name + ~1

I don't see why yall are telling him to use %allusersprofile% though it is better incase of drive letter changes, it's still the same thing. The spaces aren't the problem.

As a side note, you may need to save the % in ASCII? Open EDIT in DOS type it, save it. Then try that.I'm better the problem is that DOS thinks %120 is a variable ( the 120th argument variable)

Link to comment
Share on other sites

my problem it's sameless i've got the sintaxis but it's used by another process (explorer.exe). how can i RD \Archivos de programa\MSN Gaming Zone\Windows??*

*note that i can install windows in diferent drives so

RD /S /Q "%systemdrive%\Archivos de programa\MSN Gaming Zone"

should work if it's not used by windows

Link to comment
Share on other sites

hehe :) i had this, you've gotta use 120%% (double percent signs) to remove it, other wise it don't pick it up, annoyed me for ages!! try it with a sample folder to check.

Fix it .....thanks all you guys..

Link to comment
Share on other sites

It actually even simpler than that u just use Alcoho~1 its because of spaces not the "%" necessarely.

Also DOS short filenames support max 8 chars per name so anything that is longer considers its first 6 chars and a ~x if there are anymore same name folders/files ussually first is ~1.

If u have a dir like "A B C D" then ignore all spaces and use "ABCD~1" it works.

Also try using .cmd instead of .bat i think it uses a different emulator - cmd is better.

U can test all this in a command window as i did.

Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
  • Recently Browsing   0 members

    • No registered users viewing this page.
×
×
  • Create New...