NOTS3W Posted October 3, 2007 Share Posted October 3, 2007 D'OH!!! Link to comment Share on other sites More sharing options...
Idontwantspam Posted October 3, 2007 Author Share Posted October 3, 2007 You got it! Sorry I f-ed up on the question. It wasn't 100% my fault. You get the honor of asking the next riddle, if you can think of one. Link to comment Share on other sites More sharing options...
NOTS3W Posted October 3, 2007 Share Posted October 3, 2007 Thank you! This one is pretty simple. What is the next number in the sequence 3 3 5 4 4 3 5 5 4 _ Link to comment Share on other sites More sharing options...
anonymous_user Posted October 3, 2007 Share Posted October 3, 2007 6? Link to comment Share on other sites More sharing options...
cluberti Posted October 3, 2007 Share Posted October 3, 2007 You got it! Sorry I f-ed up on the question. It wasn't 100% my fault. I believe I mentioned you were short two prisoners at the beginning of this charade lol Link to comment Share on other sites More sharing options...
NOTS3W Posted October 3, 2007 Share Posted October 3, 2007 6?No. I believe I mentioned you were short two prisoners at the beginning of this charade lolI really can't claim to be the first or only person to have come up with the answer. I was writing up my post when Idontwantspam announced the error. At the time, I didn't even think I had the right answer given the constraints. Link to comment Share on other sites More sharing options...
NOTS3W Posted October 3, 2007 Share Posted October 3, 2007 I should also ask "why?" 6 is not correct, but even if I gave you the answer to the riddle, the next question would be "why." Otherwise, it will only take a few guesses to guess the next digit. So if you think you know the answer, also tell how it's the right answer. Link to comment Share on other sites More sharing options...
spacesurfer Posted October 3, 2007 Share Posted October 3, 2007 Here's one:There are nine iron balls exactly the same size (as in diameter, circumference, not weight), shape, color. However, only 1 weighs more than the rest. You have scales. With exactly 2 weighings, how can you determine which one weighs more than the rest.* You cannot put the balls on the scales one by one and call it one weighing. Meaning, you can't put one, then another, then another on either scale. If you want to weight 3 balls, you must put all three at once on the scale you want.* One weighing means, say for example, putting 3 balls at same time on right scale and 4 balls at same on on left scale.Other do's or don'ts will be provided based on answer.If you know the answer, do not tell us the answer, just say you know. Link to comment Share on other sites More sharing options...
Mijzelf Posted October 3, 2007 Share Posted October 3, 2007 (edited) What is the next number in the sequence 3 3 5 4 4 3 5 5 4 _3. Because 'ten' has three characters.@spacesurfer:I know. Edited October 3, 2007 by Mijzelf Link to comment Share on other sites More sharing options...
spacesurfer Posted October 3, 2007 Share Posted October 3, 2007 @spacesurfer:I know.Shhh. Link to comment Share on other sites More sharing options...
NOTS3W Posted October 3, 2007 Share Posted October 3, 2007 What is the next number in the sequence 3 3 5 4 4 3 5 5 4 _3. Because 'ten' has three characters.@spacesurfer:I know.Good job, Mijzelf! I really thought that would take longer to figure out. In case anyone didn't follow that short thread:The word "one" contains 3 letters.The word "two" contains 3 letters.The word "three" contains 5 letters.The word "four" contains 4 letters.The word "five" contains 4 letters.The word "six" contains 3 letters.The word "seven" contains 5 letters.The word "eight" contains 5 letters.The word "nine" contains 4 letters.The given sequence was 3 3 5 4 4 3 5 5 4.The next word in the series is "ten" which contains 3 letters, so the next number is 3. Link to comment Share on other sites More sharing options...
mark Posted October 3, 2007 Share Posted October 3, 2007 I made a diagram of the 1024 bottles and 8 prisoners. I don't see why my pattern won't work.1st hour has 8 vertical blocks2nd hour has 8 horizontal blocks3rd hour has 8 vertical columns for each prisonerand the 4th hour has 2 horizontal rows per prisoner.Potential of one dead prisoner and up to 4 dead.The picture is here.DL Link to comment Share on other sites More sharing options...
Mijzelf Posted October 3, 2007 Share Posted October 3, 2007 I don't have perfectly clear how you want to do this, but it seems to me that you forget that a prisoner cannot survive the 2nd hour, when he already died the 1st. Link to comment Share on other sites More sharing options...
Mijzelf Posted October 3, 2007 Share Posted October 3, 2007 A new one. Three men go fishing, and hire a boat. The boatlessor charges them for $30, so each man pays $10. While the men are walking to the landing-stage, the lessor remembers that the price is $25, so he sends his boy with $5 restitution. The boy decides that dividing $5 in three men is difficult, so he puts $2 in his pocket, and gives each man $1. Now each man has paid $9, $27 in total. The boy has $2, that makes $29. Where is the remaining dollar? Link to comment Share on other sites More sharing options...
mark Posted October 3, 2007 Share Posted October 3, 2007 I don't have perfectly clear how you want to do this, but it seems to me that you forget that a prisoner cannot survive the 2nd hour, when he already died the 1st.It is not in the second hour I have the problem, it is in the third. I could end up with two pairs of unchecked blocks as opposed to just one. Ok, so I double the tasters per column in the 3rd hour and triple in the 4th. I am ready to get as convoluted as necessary at this point. Dead men trial two.What is surprising is that, so far, I have only used 7 sips off each bottle.DL Link to comment Share on other sites More sharing options...
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