Usind the FIND command in command (batch) files

[Noise]

Maybe someone around here can help me, this is driving me crazy.

I have a text file as follows

test.txt
blahblahblah >< ewrfewtr (minutes "0")
blahblahblah >< ewrfewtr (minutes "5")
blahblahblah >< ewrfewtr (minutes "00")

I need to find all lines with (minutes "0") or (minutes "00"). So, I need to use the find command to search for the string minutes "0 and the double-quote is driving me crazy.

The following doesnt work in a cmd file:

find "minutes "0" "test.txt"
find "minutes /"0" "test.txt"
find "minutes ^"0" "test.txt"
find "minutes %"0" "test.txt"
find "minutes %%"0" "test.txt"

Notice how I try to "escape" the quote in the string. Nothing I've tried seems to work. Anyone have any ideas?

[egrath]

Hi,

use a "" to esape a double-quote:

echo minutes "0" | find /n "minutes ""0"

matches.

Bye, Egon

[Noise]

Thanks egrath...

I could have sworn I tried that!

/No more late-night script writing for me!