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Unattended installation of Win 7 installing the Grub4DOS bootloader


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Hello to everybody,

I'm trying to start the unattended installation of Windows 7 using GRUB4DOS with a different approach.

My first hard disk is partitioned like this :

(hd0,0) : Windows 7 100 MB hidden partition

(hd0,1) : partition where is installed Windows 7

This is what I did on (hd0,0) from Linux :

a) mv Boot Boot_

b) mv bootmgr bootmgr_

c) copied here the file autounattend.xml

c) copied here grldr

d) copied here menu.lst with this content inside :

title : Start the installation of Windows 7

root (hd0,1)

chainloader /bootmgr

on (hd0,1) I copied all the files and folder located on the Windows 7 DVD,so here I have these files and folders :

$Recycle.Bin

Documents and Settings

Program Files

ProgramData

Users

Windows

boot

bootmgr

efi

setup.exe

sources

support

upgrade

After having done this,I have installed the GRUB4DOS bootloader on sda from Linux,with this command :

./bootlace.com /dev/sda

and I rebooted the computer. At the boot time it asks to me to press a special key if I want to load the old bootmgr. I don't do it and the grub4dos menu appears on the screen,showing the message :

Start the installation of Windows 7

When I press a key,the installation of Windows 7 starts correctly,but the autounattend.xml file is not detected. I don't understand why,because I have copied it on the root of (hd0,0) and of (hd0,1). I read somewhere that it should be copied o the root of the disk,is this right ? What's the root in my scenario,(hd0,0)/ or (hd0,1)/ ?

Edited by Marietto
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