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luppybob

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Posts posted by luppybob

  1. Hello,

    This worked great, thanks again. Got another question along this topic ... do you know if there is away to capture a value in the registry and use it as a parameter in a command line, within the same batch file?

    For example, in a batch file, if I run the following command:

    reg query "HKLM\SOFTWARE\Intervade Software\Audit\Network" /v Destination

    My output is such:

    HKEY_LOCAL_MACHINE\SOFTWARE\Intervade Software\Audit\Network

    Destination REG_SZ 127.0.0.1

    Then, in the same batch file, I want to add "127.0.0.1" into the command line as such:

    reg add "HKLM\SOFTWARE\Intervade Software\Audit\Network" /v Destination /t REG_SZ /d 127.0.0.1 /f

    Thanks again in advance for your help.

  2. Hello,

    Thank you for your effort and prompt reply -- THIS DID WORK!

    Can you help me with one additional thing in this script:

    Basically, I want to do a couple of things if 3.1.3 is found. You had combined it in such a way, I am having difficulty inserting an "IF" statement.

    Say I want to do this:

    If [3.1.3] is found (

    echo version 3.1.3 is installed

    c:\install\Snare314.exe

    c:\install\Snare314patch.exe

    echo version 3.1.4 successfully installed

    )

    Thanks again for your great help!

  3. I am trying to do a similar thing, but my Reg Query output starts off with 4 spaces and also has a delimiter of 4 spaces, as shown below. Any idea how I can get this to work?

    Input is:

    reg query "HKLM\SOFTWARE\Microsoft\Windows\CurrentVersion\Uninstall\Snare_is1" /v DisplayVersion

    Output is:

    HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows\CurrentVersion\Uninstall\Snare_is1

    DisplayVersion REG_SZ 3.1.3

    I tried these lines in the batch file, but it did not work:

    For /f "tokens=3 delims= " %%# In (

    'Reg query "%key%" /v DisplayVersion^|Find "REG_" 2^>Nul') Do Set "rel=%%#"

    If [%rel%]==[3.1.3] echo version 3.1.3 is installed

    Thanks in advance for anyone's assistance.

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