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  1. CamTron
    Hello, I have a desktop that has Windows 7 and Windows XP installed on separate hard drives. Hard drive 1 contains Windows 7, and that's what the computer boots each time. Hard drive 2 has XP, but the only way I'm able to boot into XP is to disable hard drive 1 in the BIOS. I'd like to be able to add XP into Windows 7's boot menu so I can select which OS to boot when the computer starts up. I tried running these commands (from Windows 7): bcdedit /create {ntldr} /d "Windows XP"bcdedit /set {ntldr} device partition=F: path \ntldrbcdedit /displayorder {ntldr} /addlastI rebooted, but whenever I tried selecting "Windows XP" from the boot menu, the computer just restarts. How do I configure this correctly? I am aware of third-party tools like EasyBCD, but I'm looking for a way to do this using bcdedit on the command-line. Another thing to note is that XP labels its partition (hard drive 2) as C:, but Windows 7 labels hard drive 2 as F: (which is why I specified partition=F). Do I have to do anything extra to make sure that when XP boots, it correctly identifies its own partition as C: and not F:?
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